ST_Disjoint
Prev  7.11.1. Topological Relationships  Next

Name

ST_Disjoint — Tests if two geometries have no points in common

Synopsis

boolean ST_Disjoint( geometry A , geometry B );

Descripción

Returns true if two geometries are disjoint. Geometries are disjoint if they have no point in common.

If any other spatial relationship is true for a pair of geometries, they are not disjoint. Disjoint implies that ST_Intersects is false.

In mathematical terms: ST_Disjoint(A, B) ⇔ A ⋂ B = ∅

[Important]

Enhanced: 3.0.0 enabled support for GEOMETRYCOLLECTION

Realizado por el módulo de GEOS

[Note]

This function call does not use indexes. A negated ST_Intersects predicate can be used as a more performant alternative that uses indexes: ST_Disjoint(A,B) = NOT ST_Intersects(A,B)
[Note]

NOTE: this is the "allowable" version that returns a boolean, not an integer.

This method implements the OGC Simple Features Implementation Specification for SQL 1.1. s2.1.1.2 //s2.1.13.3 - a.Relate(b, 'FF*FF****')

This method implements the SQL/MM specification. SQL-MM 3: 5.1.26

Ejemplos

SELECT ST_Disjoint('POINT(0 0)'::geometry, 'LINESTRING ( 2 0, 0 2 )'::geometry);
 st_disjoint
---------------
 t
(1 row)
SELECT ST_Disjoint('POINT(0 0)'::geometry, 'LINESTRING ( 0 0, 0 2 )'::geometry);
 st_disjoint
---------------
 f
(1 row)

Ver también

ST_Intersects